What will be the output of the following C code?
#include <stdio.h>
void main()
{
int i = 0;
if (i == 0)
{
printf("Hello");
break;
}
}
#include <stdio.h>
void main()
{
int i = 0;
if (i == 0)
{
printf("Hello");
break;
}
}A. Hello is printed infinite times
B. Hello
C. Varies
D. Compile time error
Answer: Option D
Solution (By Examveda Team)
The correct answer is D: Compile time errorHere's why:
In C, the `break` statement is used to exit loops (like `for`, `while`, or `do-while`) or `switch` statements.
It's designed to jump out of these control structures.
In this code, `break` is placed directly inside an `if` block, but not within any loop or `switch`.
The C compiler will detect that `break` is used in an invalid context.
Therefore, the program will result in a compile-time error, indicating that the `break` statement is misplaced. The program won't even run.
In summary: The `break` statement is only valid inside loops or `switch` statements.
This Question Belongs to C Program >> Control Structures
The break statement is only allowed inside loops (for, while, do-while) or switch statements.
In this code, break; is used inside an if block, but not within any loop or switch, so the compiler will throw an error.