What will be the output of the following C code?
#include <stdio.h>
int main()
{
switch (printf("Do"))
{
case 1:
printf("First\n");
break;
case 2:
printf("Second\n");
break;
default:
printf("Default\n");
break;
}
}
#include <stdio.h>
int main()
{
switch (printf("Do"))
{
case 1:
printf("First\n");
break;
case 2:
printf("Second\n");
break;
default:
printf("Default\n");
break;
}
}A. Do
B. DoFirst
C. DoSecond
D. DoDefault
Answer: Option C
Solution (By Examveda Team)
In this code, the switch statement is evaluating the result of the printf("Do") function call. The printf() function returns the number of characters printed.When printf("Do") is executed, it prints "Do" to the standard output and returns the number of characters printed, which is 2.
So, the switch statement evaluates the value 2.
Since there is a case 2 in the switch statement, it will execute the corresponding code block, which prints "Second" to the standard output.
Therefore, the correct output of the code will be DoSecond. So, the correct answer is Option C:
DoSecond. This Question Belongs to C Program >> Control Structures
I believe there's a misunderstanding. Let's reassess the code snippet:
int main()
{
switch (printf("Do"))
{
case 1:
printf("Firstn");
break;
case 2:
printf("Secondn");
break;
default:
printf("Defaultn");
break;
}
}
```
The `printf` function inside the `switch` statement prints "Do" and returns the number of characters printed, which is 2. Therefore, the `switch` statement evaluates to `switch(2)`.
However, there's no `case 2` in the `switch` statement, so the `default` case will be executed, printing "Default".
Therefore, the output should be:
D. DoDefault
This aligns with the analysis provided earlier. So, the correct answer should be Option D, "DoDefault."