What will be the output of the following program?

public class Test{
        public static void main(String args[]){
		String s1 = "java";
		String s2 = "java";
		System.out.println(s1.equals(s2));
		System.out.println(s1 == s2); 
        }
}

In 5th line = java equals java //true
in 6th line = java == java //true
so the answer will be (D) true true

as "java" is string literal and it will be stored in string literal pool .and when second "java" added it will be checked in string literal pool if present .and it is present hence will not be overwritten rather same pointer will be returned back to s2 as well .as we know == goes by reference equality and equals goes by content as both reference and content are same hence both true true

in this program string is letral and while content is same so .equals method and == operator is give same output .And letral always present in string constant pool.in this program not create a new object.

.equals and == are the same thing

s.equals(s2) checks for values so both r same i.e. java and java
hence it is true
s1==s2 checks for references here we haven't used new keyword so both will go to constant pool but in constant pool duplicates are not allowed hence references of s1 and s2 will same
hence answer is true true

answer will be truetrue

The answer will be true true.

The option displayed is wrong.
Correct answer is option d.

Here we didn't use new to create string just say as String s1=" java"; like this only.whenever we say like this memory is created in constant pool.In constant pool duplicates are not allowed it means s1 holds java s2 also holds java so equals checks it has same content or not. And == checks it has same address or not .obviously it has same address .

== compares the objects referencing to same literals or not that why true true is the anwer

Why is the bottom statement true? is not the double equal sign a comparison of reference and not the characters of the string object?