What will be the possibility of drawing a jack or a spade from a well shuffled standard deck of 52 playing cards?
A. $$\frac{{4}}{{13}}$$
B. $$\frac{{1}}{{26}}$$
C. $$\frac{{1}}{{13}}$$
D. $$\frac{{17}}{{52}}$$
Answer: Option A
Solution (By Examveda Team)
We want jack or spadeThere are 4 jacks and 13 spade cards
Total 52 cards
Also 1 jack is jack of spades
So probability
$$\eqalign{ & = \frac{4}{{52}} + \frac{{13}}{{52}} - \frac{1}{{52}} \cr & = \frac{4}{{13}} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
Join The Discussion
Comments (1)
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
Here, in this problem serial number of options don't given properly, please review the serial number.