What will be the result of compiling and running the given code?
class A{
int b=10;
private A(){
this.b=7;
}
int f(){
return b;
}
}
class B extends A{
int b;
}
public class Test{
public static void main(String[] args){
A a = new B();
System.out.println(a.f());
}
}
class A{
int b=10;
private A(){
this.b=7;
}
int f(){
return b;
}
}
class B extends A{
int b;
}
public class Test{
public static void main(String[] args){
A a = new B();
System.out.println(a.f());
}
}A. Compilation Fails
B. Prints 0
C. Prints 10
D. Prints 7
E. None of these
Answer: Option A
Solution(By Examveda Team)
Choice A is the correct answer.
The code does not compile because the constructor of class A is declared as private. This creates a problem when the subclass constructor makes an implicit super() call to the parent class constructor at the time B is instantiated.
Since the code does not compile, all the other choices are incorrect. If the constructor of A had not been private, the output would have been 7.
This Question Belongs to Java Program >> Constructors And Methods
What is a constructor in Java?
A. A special method to create instances of classes
B. A method used for mathematical calculations
C. A method to perform string manipulations
D. An exception handling mechanism
In Java, which method is automatically called when an object is created?
A. start()
B. main()
C. init()
D. constructor()
What is method overloading in Java?
A. Defining multiple methods with the same name in the same class
B. Calling methods from another class
C. Using methods to load data from a file
D. Running methods in parallel threads
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