When a constant force acts on an object with a mass of 8 kg for a duration of 3 s. it increases the object's velocity from 4 m/s to 6 m/s . What is the magnitude of the applied force?
A. 5.33 N
B. 4.33 N
C. 6.33 N
D. 3.33 N
Answer: Option A
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Force = mass × acceleration.
Acceleration= (final velocity - initial velocity)/ time
Final velocity= 6m/s; initial velocity= 4m/s
6-4=2m/s;
Acceleration= 2/3= 0.3333
Force= 8×0.3333= 5.33N
Force = mass × acceleration
For v1, a1 = 4/3 m/s^2
For v2, a2 = 6/3 m/s^2
So, magnitude of applied force F = m×a1 - m×a2
= 5.33 N