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When a pair of dice is thrown, what is the probability of the sum of numbers being odd?
Answer & Solution
Correct Answer:
Option
D
Total events = 62 = 36
Sum odd = 1, 3, 5, 7, 9, 11
3 = (1, 2)(2, 1)
5 = (1, 4)(4, 1)(2, 3)(3, 2)
7 = (1, 6)(6, 1)(2, 5)(5, 2)(3, 4)(4, 3)
9 = (3, 6)(6, 3)(4, 5)(5, 4)
11 = (6, 5)(5, 6)
$${\text{Probability}} = \frac{{18}}{{36}} = \frac{1}{2} = 0.5$$
Sum odd = 1, 3, 5, 7, 9, 11
3 = (1, 2)(2, 1)
5 = (1, 4)(4, 1)(2, 3)(3, 2)
7 = (1, 6)(6, 1)(2, 5)(5, 2)(3, 4)(4, 3)
9 = (3, 6)(6, 3)(4, 5)(5, 4)
11 = (6, 5)(5, 6)
$${\text{Probability}} = \frac{{18}}{{36}} = \frac{1}{2} = 0.5$$
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