When the crank is at the outer dead centre, in a reciprocating steam engine, then the acceleration of the piston will be
A. $${\omega ^2}{\text{r}} \times \frac{{{\text{n}} + 1}}{{\text{n}}}$$
B. $${\omega ^2}{\text{r}} \times \frac{{{\text{n}} - 1}}{{\text{n}}}$$
C. $${\omega ^2}{\text{r}} \times \frac{{\text{n}}}{{{\text{n}} + 1}}$$
D. $${\omega ^2}{\text{r}} \times \frac{{\text{n}}}{{{\text{n}} - 1}}$$
Answer: Option B
This Question Belongs to Mechanical Engineering >> Theory Of Machine
Option B is correct.
Outer dead center pr direction of motion reverse ho jati hai.
w^r(1-n)/n Hona chahiye
Outer dead center per 180 degree hota hai to ye sayad galat answer hai