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Examveda

When the crank is at the outer dead centre, in a reciprocating steam engine, then the acceleration of the piston will be

A. $${\omega ^2}{\text{r}} \times \frac{{{\text{n}} + 1}}{{\text{n}}}$$

B. $${\omega ^2}{\text{r}} \times \frac{{{\text{n}} - 1}}{{\text{n}}}$$

C. $${\omega ^2}{\text{r}} \times \frac{{\text{n}}}{{{\text{n}} + 1}}$$

D. $${\omega ^2}{\text{r}} \times \frac{{\text{n}}}{{{\text{n}} - 1}}$$

Answer: Option B


This Question Belongs to Mechanical Engineering >> Theory Of Machine

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Comments ( 3 )

  1. Aadya Singh
    Aadya Singh :
    3 years ago

    Option B is correct.
    Outer dead center pr direction of motion reverse ho jati hai.

  2. NIRAJ KUMAR
    NIRAJ KUMAR :
    4 years ago

    w^r(1-n)/n Hona chahiye

  3. NIRAJ KUMAR
    NIRAJ KUMAR :
    4 years ago

    Outer dead center per 180 degree hota hai to ye sayad galat answer hai

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