When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder :
A. 1
B. 6
C. 8
D. Cannot be determined
Answer: Option A
Solution(By Examveda Team)
Let the number be N = 2x + 1N2 = (2x + 1)2
= 4x2 + 1 + 4x
= 4x (x + 1) + 1
Clearly, 4x (x + 1) is always divisible by 8 since one of x and (x + 1) is even which when multiplied by 4 is always divisible by 8.
Hence, required remainder = 1
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
Join The Discussion