?
Which of the following is equal to secA - cosA?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& \sec A - \cos A \cr
& = \frac{1}{{\cos A}} - \cos A \cr
& = \frac{{1 - {{\cos }^2}A}}{{\cos A}} \cr
& = \frac{{{{\sin }^2}A}}{{\cos A}} \cr
& = \tan A.\sin A \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login