Which of the following will ensure the thread will be in running state?

Solution (By Examveda Team)

Let's understand this question about threads in Java!
The question asks us which of the given options will guarantee that a thread is in the running state.
Option A: yield()
yield() suggests to the Java Virtual Machine (JVM) that the current thread is willing to relinquish its current use of a processor.
The JVM is free to ignore this suggestion. It doesn't *guarantee* the thread will stay running or give up the processor; it just offers a hint.
Option B: notify()
notify() is used for inter-thread communication.
It wakes up a single thread that is waiting on the object's monitor.
It doesn't directly put a thread into the running state; it makes a waiting thread *eligible* to run, but it might have to wait its turn.
Option C: wait()
wait() causes the current thread to *relinquish* the lock and enter the waiting state.
The thread only becomes *eligible* to run again when another thread calls notify() or notifyAll() on the same object.
So, wait() definitely does *not* ensure the thread is in the running state; it does the opposite!
Option D: Thread.killThread()
There is no standard Thread.killThread() method in Java for directly killing a thread in a safe way.
This method is not a part of Java Thread API.
Option E: None of these
Since none of the options guarantees that a thread is in a running state by their use,
hence Option E is correct
Therefore, the answer is Option E: None of these.