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Which value will show an error when stored in float(4,2)?

A. 12.11

B. 13.1

C. 1.12

D. 123.44

Answer: Option D

Solution (By Examveda Team)

This question is about how MySQL handles numbers with decimal points using the `float` data type.
Let's break down what `float(4,2)` means:
* `float`: This tells us we're working with a decimal number.
* `(4,2)`: This specifies the total number of digits (4) and the number of digits after the decimal point (2).
So, `float(4,2)` can store numbers with a maximum of 4 digits, where 2 of those digits will be after the decimal point.
Now let's look at the options:
* Option A: 12.11: This fits the criteria – 4 total digits, 2 after the decimal.
* Option B: 13.1: This also fits – 3 total digits, 1 after the decimal.
* Option C: 1.12: Again, fits the criteria – 3 total digits, 2 after the decimal.
* Option D: 123.44: This is where the problem lies. This number has 6 digits (5 before the decimal, 2 after). It's too big for the `float(4,2)` format!
Therefore, the correct answer is Option D: 123.44. This value will cause an error because it exceeds the specified size limit of the `float(4,2)` data type.

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