Examveda

With increase in temperature, the rate constant obeying Arhenious equation

A. Increases

B. Decreases

C. Decreases exponentially

D. Can either increase or decrease ; depends on the frequency factor

Answer: Option A

Solution (By Examveda Team)

According to the Arrhenius equation, the rate constant (k) increases with an increase in temperature.

The Arrhenius equation is given by: $$k = A \exp \left( -\frac{E_a}{RT} \right)$$.

Here, k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.

As the temperature T increases, the exponential term becomes larger, leading to an increase in the rate constant.

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Comments (1)

  1. Skggkp Singh
    Skggkp Singh:
    7 years ago

    Increase exponentially

Related Questions on Chemical Reaction Engineering

A first order gaseous phase reaction is catalysed by a non-porous solid. The kinetic rate constant and the external mass transfer co-efficients are k and $${{\text{k}}_{\text{g}}}$$ respectively. The effective rate constant (keff) is given by

A. $${{\text{k}}_{\text{e}}}{\text{ff}} = {\text{k}} + {{\text{k}}_{\text{g}}}$$

B. $${{\text{k}}_{\text{e}}}{\text{ff}} = \frac{{{\text{k}} + {{\text{k}}_{\text{g}}}}}{2}$$

C. $${{\text{k}}_{\text{e}}}{\text{ff}} = {\left( {{\text{k}}{{\text{k}}_{\text{g}}}} \right)^{\frac{1}{2}}}$$

D. $$\frac{1}{{{{\text{k}}_{\text{e}}}{\text{ff}}}} = \frac{1}{{\text{k}}} + \frac{1}{{{{\text{k}}_{\text{g}}}}}$$