You have the following routing table. Which of the following networks will not be placed in the neighbor routing table?
R 192.168.30.0/24 [120/1] via 192.168.40.1, 00:00:12, Serial0
C 192.168.40.0/24 is directly connected, Serial0
172.16.0.0/24 is subnetted, 1 subnets
C 172.16.30.0 is directly connected, Loopback0
R 192.168.20.0/24 [120/1] via 192.168.40.1, 00:00:12, Serial0
R 10.0.0.0/8 [120/15] via 192.168.40.1, 00:00:07, Serial0
C 192.168.50.0/24 is directly connected, Ethernet0
R 192.168.30.0/24 [120/1] via 192.168.40.1, 00:00:12, Serial0
C 192.168.40.0/24 is directly connected, Serial0
172.16.0.0/24 is subnetted, 1 subnets
C 172.16.30.0 is directly connected, Loopback0
R 192.168.20.0/24 [120/1] via 192.168.40.1, 00:00:12, Serial0
R 10.0.0.0/8 [120/15] via 192.168.40.1, 00:00:07, Serial0
C 192.168.50.0/24 is directly connected, Ethernet0
A. 172.16.30.0
B. 192.168.30.0
C. 10.0.0.0
D. All of them will be placed in the neighbor routing table
Answer: Option C
Solution(By Examveda Team)
The network 10.0.0.0 cannot be placed in the next router's routing table because it already is at 15 hops. One more hop would make the route 16 hops, and that is not valid in RIP networking.Join The Discussion
Comments ( 1 )
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A. 172.16.30.0
B. 192.168.30.0
C. 10.0.0.0
D. All of them will be placed in the neighbor routing table
i can't understand your explaination