200 kg of solids (on dry basis) is subjected to a drying process for a period of 5000 seconds. The drying occurs in the constant rate period with the drying rate as, Nc = 0.5 × 10-3 kg/m2.s. The initial moisture content of the solid is 0.2 kg moisture/kg dry solid. The interfacial area available for drying is 4 m2/1000 kg of dry solid. The moisture content at the end of the drying period is (in kg moisture/kg dry solid)
A. 0.5
B. 0.05
C. 0.1
D. 0.15
Answer: Option C
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Take 4m2/100kg
For 200kg area will be 200kg *(4 m2/100 kg)=8 m2
500=200/(8*0.5*10^-3)(xi-xf) xi=0.2
Xf=0.1
According to the answer data should be 4 m2/100 kg. So do make corrections
If u provide step it would be easy to understand