2x - ky + 7 = 0 and 6x - 12y + 15 = 0 has no solution for;
A. k = -1
B. k = -4
C. k = 4
D. k = 1
Answer: Option C
Solution (By Examveda Team)
$$\eqalign{ & {\text{For no - solution,}} \cr & \frac{{{a_1}}}{{{a_2}}} = \frac{{{b_1}}}{{{b_2}}} \ne \frac{{{c_1}}}{{{c_2}}} \cr & 2x - ky + 7 = 0{\text{ and }}6x - 12y + 15 = 0 \cr & \therefore \frac{2}{6} = \frac{{ - k}}{{12}} \cr & k = 4 \cr} $$This Question Belongs to Arithmetic Ability >> Coordinate Geometry
Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis
Join The Discussion