40 men took a dip in a pool 30 m long and 25 m broad. If the average water displaced by a man is 5 m3, then what will be the rise (in cm) in level of the pool?
A. 25
B. 26.66
C. 27.33
D. 28
Answer: Option B
Solution (By Examveda Team)
Water displaced by 40 men = 40 × 5 = 200 m3Rise in level of pool
$$\eqalign{ & = \frac{{200}}{{30 \times 25}} \cr & = \frac{8}{{30}} \times 100 \cr & = 26.66{\text{ cm}} \cr} $$
This Question Belongs to Arithmetic Ability >> Mensuration 3D
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