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A cylindrical pencil of diameter 1.2 cm has one of its end sharpened into a conical shape of height 1.4 cm. The volume of the material removed is
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& {\text{Required volume removed}} \cr
& = \pi {r^2}h - \frac{1}{3}\pi {r^2}h \cr
& = \frac{2}{3}\pi {r^2}h \cr
& = \frac{2}{3} \times \frac{{22}}{7} \times .6 \times .6 \times 1.4 \cr
& = 1.056{\text{ c}}{{\text{m}}^3} \cr} $$
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