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5 persons live in a tent. If each person requires 16 m2 of floor area and 100 m3 space for air then the height of the cone of smallest size to accommodate these persons would be?
Answer & Solution
Correct Answer:
Option
B
Let the height of cone h metre
⇒ Total area of ground will be required = 5 × 16 m2 = 80 m2
⇒ Total volume of air is needed = 100 × 5 m3 = 500 m3
According to the question
⇒ Volume of cone = 500 m3
⇒ $$\frac{1}{3}$$ × area of ground × height = 500
⇒ $$\frac{1}{3}$$ × πr2 × h = 500
⇒ $$\frac{1}{3}$$ × 80 × h = 500
⇒ Height = $$\frac{{500 \times 3}}{{80}}$$
⇒ Height of cone = 18.75 metres
⇒ Total area of ground will be required = 5 × 16 m2 = 80 m2
⇒ Total volume of air is needed = 100 × 5 m3 = 500 m3
According to the question
⇒ Volume of cone = 500 m3
⇒ $$\frac{1}{3}$$ × area of ground × height = 500
⇒ $$\frac{1}{3}$$ × πr2 × h = 500
⇒ $$\frac{1}{3}$$ × 80 × h = 500
⇒ Height = $$\frac{{500 \times 3}}{{80}}$$
⇒ Height of cone = 18.75 metres
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