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This question belongs to Electronics And Communications Engineering Electromagnetic Induction

Electromagnetic Induction

?

A 200 turn coil has an inductance of 12 mH. If the number of turns is increased to 400 turns, all other quantities (area, length etc.) remaining the same, the inductance will be

A) 6 mH B) 146 mH C) 24 mH D) 48 mH

Answer & Solution

Correct Answer: Option D

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Question posted by Examveda

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7 Comments

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Omkar Shahane 5 years ago

👍

Noob Gamer 5 years ago

L is proportional to N^2

Hence, L1/(N1)^2=L2/(N2)^2

therefore, 16*(400)^2/(200)^2=L2

=>L2=48mH

Khuram Shahzad 5 years ago

The formula is
(N^2)(D^2)/(18D + 40l)
put N=200
take other parameters as constant
then double the numbers of turns.
You will get 4* the answer

Davies Elijah 5 years ago

I need solution for this pls...

Kalpana S. 6 years ago

12 *400*400 / 200*200 = L2

Sajjad Ali 8 years ago

Hi can some one solve this how result 48 mH achieved

Sajjad Ali 8 years ago

Hi

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