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A 68 Ω resistor is connected across the terminals of a 3 V battery. The power dissipation of the resistor is

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Correct Answer: Option A
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Awais Ahmed
Awais Ahmed 2 years ago
Power = (V)^2/R.

Power = (3*3)/68 = 9/68 = 0.132Watts.

Or 0.132*1000 = 132 mWatts.