A and B start moving from places X to Y and Y to X, respectively, at the same into on the same day. After crossing each other, A and B take 549hours and 9 hours, respectively, to each their respective destinations. If the speed of A is 33 km/h, then the speed (in km/h) of B is:

S_1S_2 = sqrt t_2t_1 33S_2 = sqrt 9 949 33S_2 = 97 S_2 = 2523 km/h

This question belongs to Arithmetic Ability Speed Time And Distance

Speed Time and Distance

A and B start moving from places X to Y and Y to X, respectively, at the same into on the same day. After crossing each other, A and B take $$5\frac{4}{9}$$ hours and 9 hours, respectively, to each their respective destinations. If the speed of A is 33 km/h, then the speed (in km/h) of B is:

A) 22 B) 2 C) $$25\frac{2}{3}$$ D) $$24\frac{1}{3}$$

Answer & Solution

Correct Answer: Option C

$$\eqalign{ & \frac{{{S_1}}}{{{S_2}}} = \sqrt {\frac{{{t_2}}}{{{t_1}}}} \cr & \frac{{33}}{{{S_2}}} = \sqrt {\frac{{9 \times 9}}{{49}}} \cr & \frac{{33}}{{{S_2}}} = \frac{9}{7} \cr & {S_2} = 25\frac{2}{3}{\text{ km/h}} \cr} $$

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A and B start moving from places X to Y and...

A and B start moving from places X to Y and Y to X, respectively, at the same into on the same day. After crossing each other, A and B take $$5\frac{4}{9}$$ hours and 9 hours, respectively, to each their respective destinations. If the speed of A is 33 km/h, then the speed (in km/h) of B is:

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