A and B start moving from places X to Y and Y to X, respectively, at the same into on the same day. After crossing each other, A and B take $$5\frac{4}{9}$$ hours and 9 hours, respectively, to each their respective destinations. If the speed of A is 33 km/h, then the speed (in km/h) of B is:
A. 22
B. 2
C. $$25\frac{2}{3}$$
D. $$24\frac{1}{3}$$
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \frac{{{S_1}}}{{{S_2}}} = \sqrt {\frac{{{t_2}}}{{{t_1}}}} \cr & \frac{{33}}{{{S_2}}} = \sqrt {\frac{{9 \times 9}}{{49}}} \cr & \frac{{33}}{{{S_2}}} = \frac{9}{7} \cr & {S_2} = 25\frac{2}{3}{\text{ km/h}} \cr} $$Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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