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A man takes 6 hours 15 minutes in walking a distance and riding back to starting place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride back both ways is:
Answer & Solution
Correct Answer:
Option
C
Time taken in walking both the ways = 7 hours 45 minutes -------- (i)
Time taken in walking one way and riding back = 6 hours 15 minutes ----------- (ii)
By the equation (ii) × 2 - (i), we have,
Time taken by the man in riding both ways,
= 12 hours 30 minutes - 7 hours 45 minutes = 4 hours 45 minutes.
= 12 hours 30 minutes - 7 hours 45 minutes = 4 hours 45 minutes.
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LoginAnd, time taken in riding back = B hours
So, According to question: A + B = 6 hours 15 min. = 25/4 h
Also, 2A = 7 hours 45 min. = 31/4 h
Now, we have to find 2B.
Therefore, 2(A + B) - 2A = 2(25/4) - 31/4
After solving this, we get 2B = 19/4 h
which can be write as 4 hours 45 minutes.
Hence, option C is right answer.