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Examveda

A ball is dropped from a height of 2.25 m on a smooth floor and rises to a height of 1.00 m after the bounce. The coefficient of restitution between the ball and the floor is

A. 0.33

B. 0.44

C. 0.57

D. 0.67

Answer: Option D


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Comments ( 3 )

  1. Taofeek Akintunde
    Taofeek Akintunde :
    2 years ago

    e = v/u. This formula is Newton's law of restitution.
    Get V from V^2 =U^2 + 2gS
    U is zero (at rest)

    Get U from V^2 =U^2 + 2gS
    V is zero (comes to rest)

    e =4.4/6.64 = 0.67

  2. Rai Pratibha
    Rai Pratibha :
    3 years ago

    Cr=√(h/H)=√(1/2.25)=.67

  3. LELIN DANDASENA
    LELIN DANDASENA :
    3 years ago

    I can not understood

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The resultant of two forces P and Q acting at an angle $$\theta $$, is

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