In case of S.H.M. the period of oscillation (T), is given by
A. $${\text{T}} = \frac{{2\omega }}{{{\pi ^2}}}$$
B. $${\text{T}} = \frac{{2\pi }}{\omega }$$
C. $${\text{T}} = \frac{2}{\omega }$$
D. $${\text{T}} = \frac{\pi }{{2\omega }}$$
Answer: Option B

he relationship between angular frequency and time period is:
𝜔
=
2
𝜋
𝑇
ω=
T
2π
Rearranging for
𝑇
T:
𝑇
=
2
𝜋
𝜔
T=
ω
2π
🔹 Therefore,
𝑇
=
2
𝜋
𝜔
T=
ω
2π
give detail