A cantilever of length ‘L’ is subjected to a bending moment ‘M’ at its free end. If E$$I$$ is the flexural rigidity of the section, the deflection of the free end, is
A. $$\frac{{{\text{ML}}}}{{{\text{E}}I}}$$
B. $$\frac{{{\text{ML}}}}{{2{\text{E}}I}}$$
C. $$\frac{{{\text{M}}{{\text{L}}^2}}}{{2{\text{E}}I}}$$
D. $$\frac{{{\text{M}}{{\text{L}}^2}}}{{3{\text{E}}I}}$$
Answer: Option D
Solution(By Examveda Team)
$$\left(\frac{2}{3}\right)^3$$This Question Belongs to Civil Engineering >> Theory Of Structures
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Comments ( 19 )
A. $$\frac{2}{3}$$
B. $$\frac{3}{2}$$
C. $$\frac{5}{8}$$
D. $$\frac{8}{5}$$
Principal planes are subjected to
A. Normal stresses only
B. Tangential stresses only
C. Normal stresses as well as tangential stresses
D. None of these
A. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
B. $$\frac{{\text{I}}}{{\text{M}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
C. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{F}}}{{\text{Y}}}$$
D. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{Y}}}{{\text{F}}}$$
A. $$\frac{{\text{M}}}{{\text{T}}}$$
B. $$\frac{{\text{T}}}{{\text{M}}}$$
C. $$\frac{{2{\text{M}}}}{{\text{T}}}$$
D. $$\frac{{2{\text{T}}}}{{\text{M}}}$$
Right Anwer is C
ML^2/2EL MAXIMUM DEFLECTION
ML/EI MAXIMUM SLOPE
C is correct
ML^2/2EI
Option c is correct this one is for load at free end of contilver beam any one .......
Option c is correct this one is for load at free end of contilver beam any one .......
Option c is correct this one is for load at free end of contilver beam any one .......
ML*2/2EI
Ml³/3EI
C will be correct
defecation for cantilever with end load =PL^3/3EI
M=P*L
defecation for cantilever with end Moment =ML^2/3EI
Ml2/EI×2
C is the correct answer
Ans C option
ML SQUARE /2EI is the right answer
According to R. Aghor option C is correct.
Right answer is ML^2/2EI
this ans is wrong
the right is 3rd
slope at free end = ML/EI ,
deflection at free end =ML^2/(2EI)
Correct answer is ml^2/2EI