A car driver, driving in a fog, passes a pedestrian who was walking at the rate of 2 km/h in the same direction. The pedestrian could see the car for 6 minutes and it was visible to him up to distance of 0.6 km. what was speed of the car?
A. 30 kmph
B. 15 kmph
C. 20 kmph
D. 8 kmph
E. 12 kmph
Answer: Option D
Solution(By Examveda Team)
In 6 minutes, the car goes ahead by 0.6 km. Hence, the relative speed of the car with respect to the pedestrian is equal to 6 kmph. Hence, Net speed of the car is 8 kmph.This Question Belongs to Arithmetic Ability >> Speed Time And Distance
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Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
Let, car speed =x km/hr
Relative speed = (x-2) km/hr
6 min = 1/10 hr
Now, In 1 hour the pedestrian pass (x-2) km
So, in 1/10 hour the pedestrian pass (x-2)/10 km
ATQ,
x-2/10 =.6
Or, x-2 = .6×10
Or, x-2=6
Or,x=8
How did you get the relative speed of the car with respect to the pedestrian?
Plz tell me in details