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A car driver, driving in a fog, passes a pedestrian who was walking at the rate of 2 km/h in the same direction. The pedestrian could see the car for 6 minutes and it was visible to him up to distance of 0.6 km. what was speed of the car?
Answer & Solution
Correct Answer:
Option
D
In 6 minutes, the car goes ahead by 0.6 km. Hence, the relative speed of the car with respect to the pedestrian is equal to 6 kmph.
Hence, Net speed of the car is 8 kmph.
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Login0.6 = 6/60*(x-2)
X=8
Relative speed = (x-2) km/hr
6 min = 1/10 hr
Now, In 1 hour the pedestrian pass (x-2) km
So, in 1/10 hour the pedestrian pass (x-2)/10 km
ATQ,
x-2/10 =.6
Or, x-2 = .6×10
Or, x-2=6
Or,x=8
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