A car traveled first 36 km at 6 km/h faster than the usual speed, but it returned the same distance at 6 km/h slower than usual speed. I the total time taken by car is 8 hours, for how many hours does it traveled at the faster speed ?

Solution (By Examveda Team)

Let the original speed be S then,
Total time taken,
$$ {\frac{{36}}{{{\text{S}} - 6}}} + {\frac{{36}}{{{\text{S}} + 6}}} $$    = 8 hours
On solving the equation, we get
S = 12, -3
Then possible value of S = 12 km/h.
Thus, time taken by car at faster speed = $$\frac{{36}}{{12 + 6}}$$  = 2 hours