A car traveled first 36 km at 6 km/h faster than the usual speed, but it returned the same distance at 6 km/h slower than usual speed. I the total time taken by car is 8 hours, for how many hours does it traveled at the faster speed ?
A. 4 hours
B. 3 hours
C. 2 hours
D. 1 hours
Answer: Option C
Solution(By Examveda Team)
Let the original speed be S then,Total time taken, $$ {\frac{{36}}{{{\text{S}} - 6}}} + {\frac{{36}}{{{\text{S}} + 6}}} $$ = 8 hours On solving the equation, we get S = 12, -3 Then possible value of S = 12 km/h.Thus, time taken by car at faster speed = $$\frac{{36}}{{12 + 6}}$$ = 2 hours
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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