A car traveled first 36 km at 6 km/h faster than the usual speed, but it returned the same distance at 6 km/h slower than usual speed. I the total time taken by car is 8 hours, for how many hours does it traveled at the faster speed ?

A) 4 hours B) 3 hours C) 2 hours D) 1 hours

Answer & Solution

Correct Answer: Option C

Let the original speed be S then,
Total time taken,
$$ {\frac{{36}}{{{\text{S}} - 6}}} + {\frac{{36}}{{{\text{S}} + 6}}} $$ = 8 hours
On solving the equation, we get
S = 12, -3
Then possible value of S = 12 km/h.
Thus, time taken by car at faster speed = $$\frac{{36}}{{12 + 6}}$$ = 2 hours

Question posted by Examveda

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A car traveled first 36 km at 6 km h faster...

A car traveled first 36 km at 6 km/h faster than the usual speed, but it returned the same distance at 6 km/h slower than usual speed. I the total time taken by car is 8 hours, for how many hours does it traveled at the faster speed ?

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