A circular road runs around a circular garden. If the difference between the circumference of the outer circle and the inner circle is 44 m, the width of the road is :

A. 3.5 m

B. 4 m

C. 7 m

D. 7.5 m

Answer: Option C

Solution(By Examveda Team)

Let the radii of the outer and inner circle be R and r respectively
Then,
$$\eqalign{ & 2\pi R - 2\pi r = 44 \cr & \Rightarrow 2\pi \left( {R - r} \right) = 44 \cr & \Rightarrow \left( {R - r} \right) = \frac{{44 \times 7}}{{22 \times 2}} \cr & \Rightarrow \left( {R - r} \right) = 7 \cr} $$