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LoginGiven: Plate 'a' ~ Ka, L. Plate 'b'~Kb,2L
Concept:Apply FLHC° [Qa/A]=[Qb/A]
Ka=0.5 Kb [∆Tb/∆Ta]
Implise that: 'Ka' must be less than half times of 'Kb'....
[FLHC°= Fourier Law of Heat Conduction]