A conductor carries 125 amperes of current under 60° to a magnetic field of 1.1 tesla. The force on the conductor will be nearly
A. 50 N
B. 120 N
C. 240 N
D. 480 N
Answer: Option B
This Question Belongs to Electronics And Communications Engineering >> Electromagnetic Induction
F= BIV sin60
= 125×1.1×√3/2
= 125×1.1×0.85
= 117.7
F=IBLsin(60)
F=125×1.1×0.86
F= 118.25
Bilsinα = 1.1*125*sin60'=approx 120
Pls explain hows. 120 ans