A conductor carries 125 amperes of current under 60° to a magnetic field of 1.1 tesla. The force on the conductor will be nearly
A. 50 N
B. 120 N
C. 240 N
D. 480 N
Answer: Option B
This Question Belongs to Electronics And Communications Engineering >> Electromagnetic Induction
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Related Questions on Electromagnetic Induction
A. Self-inductance
B. Mutual inductance
C. Series aiding inductance
D. Capacitance
Which circuit element(s) will oppose the change in circuit current?
A. Resistance only
B. Inductance only
C. Capacitance only
D. Inductance and capacitance
Which of the following circuit elements will oppose the change in circuit current?
A. Capacitance
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D. All of the above
A. 2.0
B. 1.0
C. 0.5
D. Zero
F= BIV sin60
= 125×1.1×√3/2
= 125×1.1×0.85
= 117.7
F=IBLsin(60)
F=125×1.1×0.86
F= 118.25
Bilsinα = 1.1*125*sin60'=approx 120
Pls explain hows. 120 ans