A cube of length 1 cm is taken out from a cube of length 8 cm. What is the weight of the remaining portion ?
A. $$\frac{7}{8}$$ of the weight of the original cube
B. $$\frac{8}{9}$$ of the weight of the original cube
C. $$\frac{63}{64}$$ of the weight of the original cube
D. $$\frac{511}{512}$$ of the weight of the original cube
Answer: Option D
Solution(By Examveda Team)
Volume of the bigger cube = (83) cm3 = 512 cm3Volume of the cut-out cube = (13) cm3 = 1 cm3
Volume of the remaining portion = (512 - 1) cm3 = 511 cm3
$$\frac{{{\text{Weight of the remaining portion}}}}{{{\text{Weight of the original cube}}}}$$ $$ = \frac{{511}}{{512}}$$
This Question Belongs to Arithmetic Ability >> Volume And Surface Area
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