A hemispherical bowl of internal radius 12 cm contains liquid. This liquid is to be filled into cylindrical container of diameter 4 cm and height 3 cm. The number of containers that is necessary to empty the bowl is :
A. 80
B. 96
C. 100
D. 112
Answer: Option B
Solution(By Examveda Team)
Volume of hemispherical bowl :$$ = \left( {\frac{2}{3} \times \pi \times 12 \times 12 \times 12} \right)c{m^3}$$
Volume of 1 cylindrical container :
$$ = \left( {\pi \times 2 \times 2 \times 3} \right)c{m^3}$$
∴ Number of containers required :
$$\eqalign{ & = \frac{2}{3} \times \frac{{12 \times 12 \times 12}}{{2 \times 2 \times 3}} \cr & = 96 \cr} $$
Related Questions on Volume and Surface Area
A. 12$$\pi$$ cm3
B. 15$$\pi$$ cm3
C. 16$$\pi$$ cm3
D. 20$$\pi$$ cm3
In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
A. 75 cu. m
B. 750 cu. m
C. 7500 cu. m
D. 75000 cu. m
A. 84 meters
B. 90 meters
C. 168 meters
D. 336 meters
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