A is twice fast as B and B is thrice fast as C is. The journey covered by C in $$\frac{3}{2}$$ hours will be covered by A is:
A. 15 minutes
B. 20 minutes
C. 30 minutes
D. 1 hour
Answer: Option A
Solution(By Examveda Team)
Let speed of C = X Then Speed of B = 3X Then Speed of A = 6X Ratio of the speed of A and C = 1 : 6 So, Greater the speed less time taken in journey. C’s speed is 6 times less than A So A will take $$\frac{1}{6}$$ of the total time taken C to covered same distance. So, Time taken by A$$\eqalign{ & = \frac{3}{{2 \times 6}} \cr & = \frac{1}{4}\,\,{\text{hours}} \cr & = 15\,\,{\text{minutes}} \cr} $$
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
Join The Discussion