A large solid sphere is melted and moulded to form identical right circular cones with base radius and height same as the radius of the sphere. One of these cones is melted and moulded to form a smaller solid sphere. Then the ratio of the surface area of the smaller sphere to the surface area of the larger sphere is

A. $$1:{3^{\frac{4}{3}}}$$

B. $$1:{2^{\frac{3}{2}}}$$

C. $$1:{3^{\frac{2}{3}}}$$

D. $$1:{2^{\frac{4}{3}}}$$

Answer: Option D