A line cuts the x axis at the point (-3, 0) and the y-axis at the point (0, 6). What is the equation of the line?
A. x = 2y + 6
B. y = 2x - 6
C. x = 2y - 6
D. y = 2x + 6
Answer: Option D
Solution (By Examveda Team)
\[\begin{array}{*{20}{c}} {{\text{Point }}\left( { - 3,\,0} \right){\text{ and }}\left( {0,\,6} \right)} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_1}{y_1}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_2}{y_2}} \end{array}\]$$\eqalign{ & {\text{Equation of line}} \cr & y - {y_1} = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}\left( {x - {x_1}} \right) \cr & y - 0 = \frac{{6 - 0}}{{0 - \left( { - 3} \right)}}\left( {x - \left( { - 3} \right)} \right) \cr & y = \frac{6}{3}\left( {x + 3} \right) \cr & y = 2x + 6 \cr} $$
Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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