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A line cuts the x axis at the point (-3, 0) and the y-axis at the point (0, 6). What is the equation of the line?
Answer & Solution
Correct Answer:
Option
D
\[\begin{array}{*{20}{c}}
{{\text{Point }}\left( { - 3,\,0} \right){\text{ and }}\left( {0,\,6} \right)} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_1}{y_1}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_2}{y_2}}
\end{array}\]
$$\eqalign{ & {\text{Equation of line}} \cr & y - {y_1} = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}\left( {x - {x_1}} \right) \cr & y - 0 = \frac{{6 - 0}}{{0 - \left( { - 3} \right)}}\left( {x - \left( { - 3} \right)} \right) \cr & y = \frac{6}{3}\left( {x + 3} \right) \cr & y = 2x + 6 \cr} $$
$$\eqalign{ & {\text{Equation of line}} \cr & y - {y_1} = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}\left( {x - {x_1}} \right) \cr & y - 0 = \frac{{6 - 0}}{{0 - \left( { - 3} \right)}}\left( {x - \left( { - 3} \right)} \right) \cr & y = \frac{6}{3}\left( {x + 3} \right) \cr & y = 2x + 6 \cr} $$
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