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A load of 1960 N is raised at the end of...

This question belongs to Civil Engineering Theory Of Structures
Theory of Structures
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A load of 1960 N is raised at the end of a steel wire. The minimum diameter of the wire so that stress in the wire does not exceed 100 N/mm2 is:

Answer & Solution
Correct Answer: Option C
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2 Comments
Aziz Panna
Aziz Panna 6 years ago
Stress = (Load/Area)
Therefore, Area= (Load/Stress) = 1960/100 = 19.6 mm^2
Since, Area= pi × d^2 /4
So, d = root of ( area × 4 / pi) = root of (19.6 ×4 / 3.14) = 5 mm
Prakash Neupane
Prakash Neupane 8 years ago
Stress= load per unit area
100 = 1960/(3.1416*d^2/4)
Implies d= sqrt(1960*4/3.1416*100)
= 5 mm
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