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A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The efficiency of the lifting machine is

A. 50 %

B. 40 %

C. 55 %

D. 30 %

Answer: Option B

Solution(By Examveda Team)

Mechanical advantage (MA) = Load (W)/Effort (P).
MA = W/P = 500/25 = 20.
Velocity ratio (VR) = (Distance moved by the effort (Y))/(Distance moved by the load (X)).
VR = Y/X = 650/13 = 50.
Efficiency = MA/VR = 20/50 = 0.4 i.e. 40%.

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Comments ( 3 )

  1. Siddhi Ghuge
    Siddhi Ghuge :
    3 years ago

    50 % is the wrong answer
    Correct ans is 40% follow see


    Mechanical advantage (MA) = Load (W)/Effort (P).

    MA = W/P = 500/25 = 20.

    Velocity ratio (VR) = (Distance moved by the effort (Y))/(Distance moved by the load (X)).

    VR = Y/X = 650/13 = 50.

    Efficiency = MA/VR = 20/50 = 0.4 i.e. 40%.
    So option B is right

  2. Virender Sharma
    Virender Sharma :
    3 years ago

    Yes right answer is 40%

  3. Ashwani Kumar
    Ashwani Kumar :
    4 years ago

    This is wrong answer

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