A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
A. 35.55 km/hr
B. 36 km/hr
C. 71.11 km/hr
D. 71 km/hr
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{Total}}\,{\text{time}}\,{\text{taken}} \cr & = \left( {\frac{{160}}{{64}} + \frac{{160}}{{80}}} \right)hrs \cr & = \frac{9}{2}\,hrs \cr & \therefore {\text{Average}}\,{\text{speed}} \cr & = \left( {320 \times \frac{2}{9}} \right)\,{\text{km/hr}} \cr & = 71.11\,{\text{km/hr}} \cr} $$Join The Discussion
Comments ( 1 )
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
av=tt/tt
s=320/4.5=71.11