A man travelled a certain distance train at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, the distance was :
A. 25 km
B. 30 km
C. 20 km
D. 15 km
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {{\text{S}}_{{\text{average}}}} = \frac{{2ab}}{{a + b}} \cr & = \frac{{2 \times 25 \times 4}}{{25 + 4}} \cr & = \frac{{200}}{{29}}{\text{ km/hr}} \cr & {\text{Now, 2D = }}\frac{{200}}{{29}} \times \left( {5 + \frac{4}{5}} \right) \cr & = \frac{{200}}{{29}} \times \frac{{29}}{5} \cr & = 40{\text{ km}} \cr & {\text{ = D = 20 km}} \cr} $$Join The Discussion
Comments ( 1 )
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
How it will come 20