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A number of two digits has 3 for its unit's digit, and the sum of digits is $$\frac{1}{7}$$ of the itself. The number is :
Answer & Solution
Correct Answer:
Option
B
Let the ten's digit be x
Then, number = 10x + 3 and
Sum of digits = (x + 3)
So, (x + 3) = $$\frac{1}{7}$$(10x + 3)
⇔ 7x + 21 = 10x + 3
⇔ 3x = 18
⇔ x = 6
Hence, the number is :
= (10x + 3)
= (10 × 6 + 3)
= 63
Then, number = 10x + 3 and
Sum of digits = (x + 3)
So, (x + 3) = $$\frac{1}{7}$$(10x + 3)
⇔ 7x + 21 = 10x + 3
⇔ 3x = 18
⇔ x = 6
Hence, the number is :
= (10x + 3)
= (10 × 6 + 3)
= 63
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