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The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?
Answer & Solution
Correct Answer:
Option
B
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 × 2x + x) - (10x + 2x) = 36
⇒ 9x = 36
⇒ x = 4
∴ Required difference
= (2x + x) - (2x - x)
= 2x
= 8
Let ten's and unit's digits be 2x and x respectively.
Then, (10 × 2x + x) - (10x + 2x) = 36
⇒ 9x = 36
⇒ x = 4
∴ Required difference
= (2x + x) - (2x - x)
= 2x
= 8
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Login(10X+Y)
The no formed can be interchanged which is
(10Y+X)
Therefore,
(10X+Y) - (10Y+X) =36
X-Y=4
Required difference was
= (2x + x) - (2x - x)
= 2x
= 8