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Three times the first of three consecutive odd integers is 3...

This question belongs to Arithmetic Ability Problems On Numbers
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Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

Answer & Solution
Correct Answer: Option D
Let the three integers be x, x + 2 and x + 4
Then, 3x = 2(x + 4) + 3    ⇔    x = 11
∴ Third integer = x + 4 = 15
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2 Comments
Golam Muktadir
Golam Muktadir 5 years ago
Taking the three odd integers as 2n+1, 2n+3 and 2n+5 (where n>=0)

3(2n+1) = 3 + 2(2n+5)
On solving we get n=5
Putting n=5 in 2n+5 (third number), we get 15
Gurpreet Singh
Gurpreet Singh 5 years ago
Odd integers are x, x+1, x+3 = 3x= 2 (x+3) = 3x = 2x + 6x , x= 9
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