A person has to cover a distance of 160 km in 15 hours. If he covers $$\frac{4}{5}$$ of the distance in $$\frac{2}{3}$$ of the time, then what should be his speed (in km/h) to cover the remaining distance in the remaining time?

Solution (By Examveda Team)

$${\frac{4}{5}^{{\text{th}}}}$$ part of distance $$ = 160 \times \frac{4}{5} = 128$$
Remaining distance = 32 km
$${\frac{2}{3}^{{\text{th}}}}$$ of time $$ = 15 \times \frac{2}{3} = 10{\text{ hr}}$$
Remaining time = 5 hr
Speed $$ = \frac{{32}}{5} = 6.4{\text{ km/hr}}$$