A person travels a distance of 300 m and then returns to the starting point. The time taken by him for the outward journey is 5 hours more than the time taken for the return journey. If he returns at a speed of 10 km/h more than the speed of going, what is the average speed (in km/h) for the entire journey?
A. 20
B. 15
C. 24
D. 30
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \frac{{300}}{{x + 10}} - \frac{{300}}{x} = 5 \cr & 60\left[ {\frac{{10}}{{x\left( {x + 10} \right)}}} \right] = 1 \cr & 600 = x\left( {x + 10} \right) \cr & {\text{Put }}x = 20 \cr & {\text{Average speed}} = \frac{{2 \times 20 \times 30}}{{20 + 30}} \cr & = \frac{{2 \times 600}}{{50}} \cr & = 24{\text{ km/hr}} \cr} $$Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
Join The Discussion