A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for both the trips ?
A. 36 kmph
B. 45 kmph
C. 48 kmph
D. 50 kmph
Answer: Option C
Solution(By Examveda Team)
Speed on return trip = 150% of 40 = 60 kmph∴ Average speed :
$$\eqalign{ & = \left( {\frac{{2 \times 40 \times 60}}{{40 + 60}}} \right){\text{kmph}} \cr & = \left( {\frac{{4800}}{{100}}} \right){\text{kmph}} \cr & = 48{\text{ kmph}} \cr} $$
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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