A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for both the trips ?

Solution (By Examveda Team)

Speed on return trip = 150% of 40 = 60 kmph
∴ Average speed :
$$\eqalign{ & = \left( {\frac{{2 \times 40 \times 60}}{{40 + 60}}} \right){\text{kmph}} \cr & = \left( {\frac{{4800}}{{100}}} \right){\text{kmph}} \cr & = 48{\text{ kmph}} \cr} $$